-7^3+10x^2-3x=0

Solution for -7^3+10x^2-3x=0 equation:

-7^3+10x^2-3x=0

We add all the numbers together, and all the variables

10x^2-3x-343=0

a = 10; b = -3; c = -343;
Δ = b2-4ac
Δ = -32-4·10·(-343)
Δ = 13729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{13729}}{2*10}=\frac{3-\sqrt{13729}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{13729}}{2*10}=\frac{3+\sqrt{13729}}{20}
$